Abs(12x^2+5x-7)=4

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Solution for Abs(12x^2+5x-7)=4 equation: 


Simplifying
Abs(12x2 + 5x + -7) = 4

Reorder the terms:
bsA(-7 + 5x + 12x2) = 4
(-7 * bsA + 5x * bsA + 12x2 * bsA) = 4
(-7bsA + 5bsxA + 12bsx2A) = 4

Solving
-7bsA + 5bsxA + 12bsx2A = 4

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Reorder the terms:
-4 + -7bsA + 5bsxA + 12bsx2A = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + -7bsA + 5bsxA + 12bsx2A = 0

The solution to this equation could not be determined.

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